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Jul 17, 2021 at 19:38 comment added Omar Antolín-Camarena I tried commenting on Thuses, but it won't let me register. You define a map $\phi_b : A \to A$ by $\phi_b(a) = \pi_A(A'_b)$ which does not seem to be an element of $A$. Did you mean $\phi_b(a) = \pi_A(f(a,b))$?
Jul 14, 2021 at 22:09 history answered V. Rogov CC BY-SA 4.0