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Apr 13, 2017 at 12:19 history edited CommunityBot
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Oct 21, 2013 at 17:56 answer added Qiaochu Yuan timeline score: 3
Sep 27, 2010 at 16:59 vote accept Fiktor
Sep 24, 2010 at 12:59 answer added Tom Goodwillie timeline score: 3
Sep 24, 2010 at 2:18 comment added Tom Goodwillie But surely the usual flow associated to a smooth tangent vector field on a smooth closed manifold does not satisfy the condition written down in the question for an <i>arbitrary</i> $\mathbb R$-linear map $h:A\to\mathbb R$.
Sep 24, 2010 at 2:03 comment added Tom Goodwillie Formal power series rings? Rings of analytic functions?
Sep 23, 2010 at 23:07 history edited Fiktor CC BY-SA 2.5
Adding an example
Sep 23, 2010 at 19:09 comment added Yemon Choi I may have misunderstood your question; but if I recall correctly there are commutative algebras A which admit no non-zero derivation from A to A -- in fact every semisimple Banach algebra has this property, this is Marc Thomas' improvement on the Singer-Wermer theorem. (Note that I'm not assuming the derivation is continuous.) I suspect that if A has no non-zero derivations, then every derivation will be a flow -- but this is somehow not the kind of example you are looking for...
Sep 23, 2010 at 17:33 history edited Fiktor CC BY-SA 2.5
typo
Sep 23, 2010 at 17:27 comment added Fiktor @Theo Johnson-Freyd Yes, "non-compact". Corrected. Thank you.
Sep 23, 2010 at 17:26 history edited Fiktor CC BY-SA 2.5
typo
Sep 23, 2010 at 16:32 comment added Theo Johnson-Freyd There is some typo in "1'. Algebra $C^\infty(M)$ of smooth functions on a compact manifold without boundary". Presumably you mean "non-compact"? In any case, nice question overall.
Sep 23, 2010 at 14:09 answer added Greg Muller timeline score: 4
Sep 23, 2010 at 13:21 history asked Fiktor CC BY-SA 2.5