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Jul 8, 2021 at 9:57 comment added Benoît Kloeckner Note that in $\mathbb{R}^n$, if (1) is true for a compact set $K$ then $K$ must be convex. This is interstingly not true in $\mathbb{H}^n$, where horospheres are not flat. You can see that as several variants of convexity that no longer match (using either geodesic or busemann functions).
Jul 8, 2021 at 6:00 vote accept asv
Jul 8, 2021 at 3:56 answer added Mohammad Ghomi timeline score: 7
Jul 7, 2021 at 14:31 comment added asv @LeoMoos: to be more precise one should consider everything in open half-sphere rather than sphere.
Jul 7, 2021 at 14:13 comment added Leo Moos Are you sure about (1) holding in spherical space? If $\pm p \in \mathbf{S}^n$ are antipodal and $D_r(p)$ is a closed disc around $p$, then the nearest points to $-p$ form $\partial D_r(p)$, no?
Jul 7, 2021 at 9:42 history edited asv
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Jul 7, 2021 at 7:12 comment added markvs It is true in every CAT(0) space. Must be in Bridson-Haefliger.
Jul 7, 2021 at 6:50 history asked asv CC BY-SA 4.0