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Jul 7, 2021 at 1:38 comment added Master Gang @varret Thanks.
Jul 7, 2021 at 1:14 history edited verret CC BY-SA 4.0
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Jul 7, 2021 at 1:11 comment added verret I fixe the construction.
Jul 7, 2021 at 1:08 history edited verret CC BY-SA 4.0
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Jul 6, 2021 at 8:32 comment added Master Gang @varret We must have $C_G(N)\leq N$ since $N=F(G)$ and $G$ is solvable. But this is impossible.
Jul 6, 2021 at 8:30 comment added Master Gang @varret There may be some mistake in your example. When m=2, the group you constructed is of order 72, and it's not difficult to show that $O_2(G)=1, O_3(G)=N$.
Jul 5, 2021 at 6:54 comment added Master Gang Thanks for your useful answer.
Jul 5, 2021 at 6:41 vote accept Master Gang
Jul 5, 2021 at 5:30 history edited verret CC BY-SA 4.0
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Jul 5, 2021 at 5:21 history answered verret CC BY-SA 4.0