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Jul 3, 2021 at 17:37 vote accept G. Blaickner
Jul 3, 2021 at 17:37 comment added G. Blaickner Okay, great! Thank you again!
Jul 3, 2021 at 17:37 comment added Igor Khavkine @G.Blaickner You got it!
Jul 3, 2021 at 17:34 comment added G. Blaickner Okay, thank you very much for your answer. So, to understand correctly, $I_{j_{1}j_{2}}^{j_{3}}$ in your notation is the (unique up to multiple) intertwiner of the form $I_{j_{1}j_{2}}^{j_{3}}:V_{j_{3}}\to V_{j_{2}}\otimes V_{j_{2}}$ and hence, using your formula, the matrix coefficients of this intertwiner are exactly given by $(-1)^{-j_{1}+j_{2}+m_{3}}\sqrt{2j_{3}+1}$ times the $3j$-symbol?
Jul 3, 2021 at 17:19 history answered Igor Khavkine CC BY-SA 4.0