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Jul 3, 2021 at 4:39 history became hot network question
Jul 2, 2021 at 21:46 answer added Danny Ruberman timeline score: 9
Jul 2, 2021 at 21:41 comment added lemon314 @RyanBudney, you misunderstand: the input is the Seifert fibration, say $\{g, e, (a_{i}/b_{i})\}$. The output is to be a balanced presentation of its fundamental group. Not the other way round.
Jul 2, 2021 at 21:22 comment added Ryan Budney You can't derive the Seifert invariants from the fundamental group. At least, not if you are considering it as only a group. If you use presentations you could give the group additional structure -- marked subgroups, etc.
Jul 2, 2021 at 21:12 comment added lemon314 @RyanBudney, I meant the classifying invariants of the Seifert space (it's symbols, if you will). They do classify the Seifert spaces, and therefore encode balanced presentations of their fundamental groups - so I ask about these presentations expressed in terms of these invariants.
Jul 2, 2021 at 21:00 comment added Ryan Budney I'm a little confused. In general, Seifert fibered spaces can't be classified by their fundamental group -- for example, see Lens spaces.
Jul 2, 2021 at 20:39 history asked lemon314 CC BY-SA 4.0