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Jul 2, 2021 at 15:01 comment added AMath91 Yes, that’s exactly what I need. I’ll ask a new question. Thanks!
Jul 2, 2021 at 14:51 comment added Stefan Witzel Perhaps it's really time you asked a new question. How would $x$ and $y$ be contained in a common chamber in a non-discrete building? I think the statement that is still true (and implies the above in the discrete case) is that for a point $z \in X$ and a point $\xi \in \partial X$ there is an apartment containing both. (You recover the above by taking $z$ to be an interior point of the chamber.) I guess, what you want is an apartment that contains a germ from $x$ (toward y) as well as $\xi$ in the boundary and that could well be true, but I don't have a reference ready for that.
S Jul 2, 2021 at 14:42 vote accept AMath91
S Jul 2, 2021 at 14:42 vote accept AMath91
S Jul 2, 2021 at 14:42
Jul 2, 2021 at 14:42 vote accept AMath91
S Jul 2, 2021 at 14:42
Jul 2, 2021 at 14:42 comment added AMath91 Do you know if that result holds for non-discrete buildings as well? I’m confused about which results of that book hold in general or only in the discrete case.
Jul 2, 2021 at 14:40 comment added Stefan Witzel Theorem (1) on page 170 of Brown "Buildings".
Jul 2, 2021 at 14:39 answer added Stefan Witzel timeline score: 1
Jul 2, 2021 at 14:35 comment added AMath91 Do you have a reference for this? I’m a novice at buildings and I haven’t found this result in the axioms.
Jul 2, 2021 at 14:11 comment added Stefan Witzel yes given a chamber and a point at infinity you can find an apartment that contains the apartment and the point at infinity. This apartment being convex and containing $x$ as well as the endpoint of $\rho$, it will contain all of $\rho$.
Jul 2, 2021 at 12:08 comment added AMath91 I wanted to use an argument like this, but I’m worried that this apartment will not contain the whole ray $\rho$. Assuming $x$ and $y$ are in the a common chamber, can I always find an apartment containing $y$, $x$ and $\rho$?
Jul 2, 2021 at 12:03 comment added AMath91 In view of HJRW’s answer, is the statement true if I change obtuse with not acute (so I allow $\pi/2$)?
Jul 2, 2021 at 10:47 comment added Stefan Witzel If "close" means that x and y lie in a common (closed) chamber then you can take an apartment that contains that chamber and contains xi in its boundary. Then you can use that what you want is a "known fact" for Euclidean spaces (specifically this apartment).
Jul 2, 2021 at 10:16 history became hot network question
Jul 2, 2021 at 7:53 answer added HJRW timeline score: 5
Jul 1, 2021 at 22:55 history asked AMath91 CC BY-SA 4.0