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Jun 29, 2021 at 6:30 comment added Francesco Polizzi btw, in my last comment "unirational" should be "uniruled".
Jun 27, 2021 at 15:34 vote accept Ron
Jun 27, 2021 at 9:46 comment added Francesco Polizzi Ok, I wrote a short answer
Jun 27, 2021 at 9:45 answer added Francesco Polizzi timeline score: 6
Jun 27, 2021 at 9:28 comment added Ron @FrancescoPolizzi Thanks. You could write your comments as the answer. This does answer my question to a large extent.
Jun 27, 2021 at 9:25 comment added Francesco Polizzi unirational, but not rational in general. If you blow-up a smooth curve $C$ of genus $g\geq 1$ in $\mathbb{P}^3$, the exceptional divisor is a $\mathbb{P}^1$-bundle over $C$, that is not rational because it has irregularity $g$.
Jun 27, 2021 at 9:20 comment added Ron @FrancescoPolizzi By your argument that it is the Proj of a normal sheaf, can't we further say that the irreducible components of the exceptional divisor must be rational?
Jun 26, 2021 at 18:45 comment added Francesco Polizzi Is not the exceptional divisor always covered by rational curves (because it is the Proj of the normal sheaf)? This should exclude all the non-uniruled varieties, I think.
Jun 26, 2021 at 18:21 history asked Ron CC BY-SA 4.0