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Nov 2, 2021 at 20:04 review Close votes
Nov 12, 2021 at 12:24
Jun 18, 2021 at 18:19 vote accept Pedja
Jun 18, 2021 at 17:16 answer added Max Alekseyev timeline score: 10
Jun 18, 2021 at 6:09 comment added Dan Romik Not sure if it helps, but using Mathematica I found that $U(n,2,1-m)$ has the explicit formula $U(n,2,1-m)=\sum_{k=0}^{\lfloor n/2 \rfloor} \binom{n}{2k+1} m^k$. This should be easy to prove using the generating function.
Jun 18, 2021 at 3:47 history asked Pedja CC BY-SA 4.0