Skip to main content
7 events
when toggle format what by license comment
Jun 18, 2021 at 14:56 comment added fosco Yes, I wanted to add it myself. :)
Jun 18, 2021 at 13:27 comment added Martin Brandenburg To sum this up, we have$$\int^{B} \hom(A,B) \times \hom(B,C) = \hom(A,C).$$In fact, for any set-valued functor $F$ we have $$\int^{B} F(B) \times \hom(B,C) = F(C).$$
Jun 17, 2021 at 20:55 comment added fosco There's a very long story you can tell about them :D arxiv.org/abs/1501.02503
Jun 17, 2021 at 20:40 comment added Johan Thiborg-Ericson On a first glance, this looks very much like what I am looking for. I'll look into cowedges.
Jun 17, 2021 at 19:54 history edited fosco CC BY-SA 4.0
added 8 characters in body
Jun 17, 2021 at 9:49 history edited fosco CC BY-SA 4.0
added 686 characters in body
Jun 17, 2021 at 9:43 history answered fosco CC BY-SA 4.0