Timeline for Infinite, finitely generated linear group has indices of subgroups divisible by infinitely many primes
Current License: CC BY-SA 4.0
5 events
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Jun 18, 2021 at 1:59 | comment | added | spin | I see, thanks, that argument seems better. | |
Jun 17, 2021 at 19:15 | comment | added | YCor | For the first argument: in an arbitrary topological space, if a subset $X$ has closure $Y$ and $Y'$ is clopen in $Y$, then $X\cap Y'$ has closure $Y'$ (so no argument using irreducibility or dimension is needed). So, yes, this allows to reduce to connected Zariski closure. | |
Jun 17, 2021 at 9:47 | comment | added | spin | I should have mentioned that my question was motivated from looking at a proof in MR0387428. There they claim the positive answer follows from the result of Platonov (10.4 in Wehrfritz), but in positive characteristic this does not seem to be clear. | |
Jun 17, 2021 at 9:42 | comment | added | spin | Thank you for the answer. Some details, just to make sure I understand the beginning correctly. Let $S$ be the Zariski closure of $G$. Then $S/S^\circ$ is finite. Thus $G/G \cap S^\circ$ is finite, so $G \cap S^\circ$ is finitely generated. Furthermore, The Zariski closure of $G \cap S^\circ$ has the same dimension as $S^\circ$, so it must be equal to $S^\circ$. So we can assume that $G$ has connected Zariski closure $S$. | |
Jun 15, 2021 at 12:32 | history | answered | YCor | CC BY-SA 4.0 |