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Jun 18, 2021 at 1:59 comment added spin I see, thanks, that argument seems better.
Jun 17, 2021 at 19:15 comment added YCor For the first argument: in an arbitrary topological space, if a subset $X$ has closure $Y$ and $Y'$ is clopen in $Y$, then $X\cap Y'$ has closure $Y'$ (so no argument using irreducibility or dimension is needed). So, yes, this allows to reduce to connected Zariski closure.
Jun 17, 2021 at 9:47 comment added spin I should have mentioned that my question was motivated from looking at a proof in MR0387428. There they claim the positive answer follows from the result of Platonov (10.4 in Wehrfritz), but in positive characteristic this does not seem to be clear.
Jun 17, 2021 at 9:42 comment added spin Thank you for the answer. Some details, just to make sure I understand the beginning correctly. Let $S$ be the Zariski closure of $G$. Then $S/S^\circ$ is finite. Thus $G/G \cap S^\circ$ is finite, so $G \cap S^\circ$ is finitely generated. Furthermore, The Zariski closure of $G \cap S^\circ$ has the same dimension as $S^\circ$, so it must be equal to $S^\circ$. So we can assume that $G$ has connected Zariski closure $S$.
Jun 15, 2021 at 12:32 history answered YCor CC BY-SA 4.0