Timeline for Linear combinations of roots of unity
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Oct 10 at 9:29 | history | edited | Emil Jeřábek | CC BY-SA 4.0 |
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| Oct 10 at 9:16 | comment | added | Emil Jeřábek | @JingweiChen I don’t know what exactly you are referring to, as “$\sqrt{|1-\omega|}$” does not appear anywhere in my post. Anyway, you are wrong. As I am using repeatedly, $|1-\omega|=2\sin\frac\pi n$; you can readily show this by doing the algebra, or alternatively, just look at a picture ($A=0$, $D=1$, $B=\omega$, $\theta=\pi/n$, $|1-\omega|=|BD|$). It is certainly larger than $1-\cos\frac\pi n$ (which is the distance from $C$ to the intersection point of the circle with line $AC$). | |
| Oct 10 at 6:09 | comment | converted from answer | Jingwei Chen | $\sqrt{|1-\omega|}$ is not equal to $\sin(\frac{\pi}{n})$, but $\sqrt{1-\cos(\frac{\pi}{n})}$. | |
| Jun 8, 2021 at 17:50 | comment | added | Emil Jeřábek | You’re welcome. | |
| Jun 8, 2021 at 15:15 | vote | accept | Beni Bogosel | ||
| Jun 8, 2021 at 15:15 | comment | added | Beni Bogosel | Thank you very much for performing the computations! Nice answer. | |
| Jun 7, 2021 at 18:49 | history | edited | Emil Jeřábek | CC BY-SA 4.0 |
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| Jun 7, 2021 at 17:03 | history | answered | Emil Jeřábek | CC BY-SA 4.0 |
