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S Jun 20, 2021 at 15:03 history bounty ended CommunityBot
S Jun 20, 2021 at 15:03 history notice removed CommunityBot
Jun 16, 2021 at 16:12 comment added Alexander Braverman Actually, I think I proved it in the case when $\mathcal E$ is very stable, which is what I needed in the first place. But I don't know if it is true for stable bundles (I don't understand what you mean by taking limit here).
Jun 15, 2021 at 13:17 comment added Evgeny Shinder Actually, I think if you assume the statement for stable $\mathcal{E}$, then the one for general $\mathcal{E}$ may follow by the following induction argument: consider the HN filtration on $\mathcal{E}$, and take its limit to the special fiber.
Jun 14, 2021 at 19:20 comment added Evgeny Shinder If you restrict to only semistable bundles, then points of the coarse moduli space are S-equivalence classes which is kind of a filtration like you ask?
Jun 14, 2021 at 14:13 comment added Mohan It is possible to construct a family with general member trivial (direct sum of the structure sheaf) and special member indecomposable.
Jun 14, 2021 at 13:42 comment added Alexander Braverman Yes, but frankly I don't think it should be true for arbitrary $\mathcal E$. But I do believe that it should be true if you impose some stability requirements on $\mathcal E$ (I certainly think that it should be true for very stable bundles, maybe also for just stable ones).
Jun 14, 2021 at 2:33 comment added Mohan Just so that I understand. If you had a family of vector bundles, say of rank 2, with all isomorphic for $t\neq 0$ and at zero it is indecomposable, you want the special member isomorphic to the general? If false, will it give you an example for question 1?
S Jun 12, 2021 at 12:33 history bounty started Alexander Braverman
S Jun 12, 2021 at 12:33 history notice added Alexander Braverman Draw attention
Jun 11, 2021 at 14:06 answer added Angelo timeline score: 1
Jun 7, 2021 at 16:51 answer added Mohan timeline score: 3
Jun 7, 2021 at 13:32 history asked Alexander Braverman CC BY-SA 4.0