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Timeline for Fiber product of group rings

Current License: CC BY-SA 4.0

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Jun 3, 2021 at 21:10 comment added R. van Dobben de Bruyn One possible way to prove something like this is if the free functor $F \colon \mathbf{Gp} \to \mathbf{Hopf}_K$ has a left adjoint. It does have a right adjoint given by grouplike elements, but I have no idea if it has a left adjoint (this would imply much more limits commute, which is maybe too optimistic).
Jun 3, 2021 at 20:15 comment added Benjamin Steinberg It seems the tensor product is the product so I withdraw my objection.
Jun 3, 2021 at 20:06 comment added Benjamin Steinberg @R.vanDobbendeBruyn sorry I hadn't caught that it was taken in hopf algebras. That's out of my pay grade
Jun 3, 2021 at 20:02 comment added R. van Dobben de Bruyn @BenjaminSteinberg is the product in Hopf algebras really just the direct product? I can't think of a natural comultiplication on that. (Analogously, in the commutative case, the coproduct in affine group schemes is not given by disjoint union, as the latter does not have a natural group structure.)
Jun 3, 2021 at 19:45 comment added Benjamin Steinberg This seems false. If G is trivial, on the left side you have the tensor product of group rings and in the right the direct product
Jun 3, 2021 at 17:52 history asked Hadrian Heine CC BY-SA 4.0