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Jun 4, 2021 at 2:22 vote accept Ron
Jun 3, 2021 at 10:34 comment added Puzzled It is ok when $\mathcal{X}$ is a surface and $\pi$ has connected fibers. In this case you do not need the general fiber to be smooth, irreducible is enough.
Jun 2, 2021 at 16:13 comment added Jason Starr According to a conjecture of Gino Fano, the total space of a sufficiently general conic bundle over a rational surface, say $\mathbb{P}^1\times\mathbb{P}^1$, is not unirational. This would give a counterexample to all three of your properties via projection to one of the two $\mathbb{P}^1$ factors.
Jun 2, 2021 at 16:04 answer added abx timeline score: 7
Jun 2, 2021 at 14:28 history asked Ron CC BY-SA 4.0