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Jun 12, 2021 at 10:07 comment added Anixx The linked paper seems to have errors, and I have identified at least two. The monomials should regularize to zero in fact. I wonder, what is the source for the first integral?
Jun 6, 2021 at 17:26 comment added Anixx Is there a source for the first integral?
Jun 6, 2021 at 12:01 comment added Carlo Beenakker mathoverflow.net/questions/394643/…
Jun 6, 2021 at 10:51 comment added Anixx The regularization value of 0 can be verified with Mathematica: f[x_] := x^p; Limit[s Sum[f[s x],{x,1,Infinity},Regularization->"Dirichlet"],s->0]
Jun 6, 2021 at 10:29 comment added Anixx I have the following formula: $\int_0^\infty x^n dx=\frac{\left(\tau +\frac{1}{2}\right)^{n+2}-\left(\tau -\frac{1}{2}\right)^{n+2}}{(n+1)(n+2)}=\frac{\omega _+^{n+2}-\omega _-^{n+2}}{(n+1)(n+2)}$ which regularizes to $\frac{B_{n+2}(1)-B_{n+2}(0)}{(n+1)(n+2)}$, which is zero. Integrals of monomials always regularize rto zero as far as I know.
Jun 5, 2021 at 3:49 comment added Piotr Hajlasz More details to your interesting answer are welcome. I am sure you, as a physicist can do it. Otherwise from the mathematical point of view your answer is along the medieval proof of the existence of God: 0=(1-1)+(1-1)+...=1+(-1+1)+(-1+1)+...=1. Something was created from nothing. God exists!!!
Jun 4, 2021 at 4:58 comment added Anixx Hmm, this is not in line with the regularization methods I know, on my clock, an integral of monomial from 0 to infinity regularizes to 0.
Jun 2, 2021 at 17:05 comment added Carlo Beenakker "=" because I am too timid to write $\int_0^\infty x\,dx=1/6$.
Jun 2, 2021 at 16:24 comment added Soleil Why is the = double quoted ?
Jun 2, 2021 at 12:33 history answered Carlo Beenakker CC BY-SA 4.0