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May 31, 2021 at 22:17 vote accept Aileann D. PRET
May 31, 2021 at 16:43 comment added Aileann D. PRET I would like some expansion for the values of the Dissidences. (I meant that, in this case, it was $1$ : since I was talking about Dissidence over the whole real set and not only over a finite interval (where it could have been larger than $1$), $\lim_{x\to\infty}\frac{x+2(\sqrt{2}-1)}{x}=1$).
May 31, 2021 at 10:28 answer added Carlo Beenakker timeline score: 2
May 31, 2021 at 3:41 review Close votes
Jun 18, 2021 at 3:04
May 31, 2021 at 3:24 history edited LSpice CC BY-SA 4.0
Typo
May 31, 2021 at 3:24 comment added LSpice In what form would you like the answer? (Also, what do you mean by "$\delta_G[\mathcal T]$ can't be different from $1$"?)
May 31, 2021 at 1:27 review First posts
May 31, 2021 at 4:06
May 31, 2021 at 1:17 history asked Aileann D. PRET CC BY-SA 4.0