Timeline for Convex varieties that are not homogeneous
Current License: CC BY-SA 2.5
16 events
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| Sep 24, 2010 at 11:27 | comment | added | Calc | Thank you very much for your answer and the related comments. It seems this would be an insightful example for proving that convex+rationally connected implies homogeneous. | |
| Sep 21, 2010 at 6:42 | vote | accept | Calc | ||
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| Sep 21, 2010 at 6:42 | vote | accept | Calc | ||
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| Sep 20, 2010 at 21:47 | comment | added | mdeland | This is nice. By looking at the mrc fibration, conjecturally examples would all have to be of this form: they would map to a variety with no rational curves on them and the fibers would be homogeneous spaces. This also encompasses Angelo's examples. (Of course, the fibration is only a rational map in general...) | |
| Sep 20, 2010 at 21:22 | vote | accept | Calc | ||
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| Sep 20, 2010 at 21:20 | history | edited | Francesco Polizzi | CC BY-SA 2.5 |
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| Sep 20, 2010 at 21:12 | history | edited | Francesco Polizzi | CC BY-SA 2.5 |
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| Sep 20, 2010 at 21:05 | history | edited | Francesco Polizzi | CC BY-SA 2.5 |
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| Sep 20, 2010 at 17:39 | comment | added | Francesco Polizzi | Ops, you are right. I don't know why, I was thinking only about (generically) injective maps. I will edit the answer. | |
| Sep 20, 2010 at 17:31 | comment | added | mdeland | If you take a map \PP^1 \rightarrow X which is a multiple cover of the exceptional divisor E, then you will produce a rational curve on X where the convexity condition fails. | |
| Sep 20, 2010 at 17:18 | history | edited | Francesco Polizzi | CC BY-SA 2.5 |
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| Sep 20, 2010 at 17:02 | history | edited | Francesco Polizzi | CC BY-SA 2.5 |
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| Sep 20, 2010 at 16:59 | history | undeleted | Francesco Polizzi | ||
| Sep 20, 2010 at 16:57 | history | edited | Francesco Polizzi | CC BY-SA 2.5 |
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| Sep 20, 2010 at 16:16 | history | deleted | Francesco Polizzi | ||
| Sep 20, 2010 at 16:07 | history | answered | Francesco Polizzi | CC BY-SA 2.5 |