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May 30, 2021 at 11:21 comment added YCor Is "more than" meant to be "$\ge$"? If $G$ is abelian and $\phi$ surjective there's indeed equality, as already observed by several users. This applies more generally for $G=H\times A$, $\phi$ trivial on $H$ and surjective on $A$ abelian. Are there other cases? We might expect a proof of $\ge$ to help classify the cases of equality.
May 29, 2021 at 17:18 comment added LSpice @MarkWildon's answer, referenced above. \\ Name of these notes, referenced by @‍lambda: Wagner - Introduction to combinatorial enumeration.
May 29, 2021 at 15:48 history edited YCor CC BY-SA 4.0
edited tags, added implicit assumption
May 29, 2021 at 11:20 comment added Mark Wildon My answer below includes a reference to this paper of Gupta sciencedirect.com/science/article/pii/0097316576900510 that gives a bijective proof of the partition identity.
May 29, 2021 at 11:16 answer added Mark Wildon timeline score: 10
May 29, 2021 at 10:34 answer added Geoff Robinson timeline score: 5
S May 29, 2021 at 4:06 vote accept Clark Lyons
May 29, 2021 at 2:28 answer added LSpice timeline score: 11
May 29, 2021 at 1:21 comment added lambda The equivalence of this identity with the one in the post linked by David is pretty easy, but it appears in exactly this form as chapter 9 exercise 7 of these notes. My guess is that this one doesn't appear in standard sources because it's straightforwardly equivalent to that better-known identity (attributed to Euler in Andrews's book) even though this formulation is in some ways more natural.
May 28, 2021 at 20:18 answer added Clark Lyons timeline score: 13
May 28, 2021 at 12:32 comment added David E Speyer Regarding the partition identity, see math.stackexchange.com/questions/92191 .
May 28, 2021 at 7:21 vote accept Clark Lyons
S May 29, 2021 at 4:06
May 28, 2021 at 6:56 vote accept Clark Lyons
May 28, 2021 at 6:56
May 28, 2021 at 6:29 comment added Gerry Myerson The stackexchange post is math.stackexchange.com/questions/4153508/… The general rule here is you wait for several days before posting to a second site, and you link the two posts to spare people from duplication of effort.
May 28, 2021 at 3:27 answer added David E Speyer timeline score: 13
May 28, 2021 at 2:00 comment added David E Speyer Partitions with distinct odd parts are in easy bijection with self conjugate partitions. I think I've seen it in that guise but am not sure where.
May 28, 2021 at 1:49 comment added lambda I have seen that partition identity before, though unfortunately not in a publicly available source. I suspect it is "well known" but I'm not sure off the top of my head the best place to look.
May 28, 2021 at 1:35 answer added Buzz timeline score: 2
May 28, 2021 at 0:18 review First posts
May 28, 2021 at 6:43
May 28, 2021 at 0:15 history asked Clark Lyons CC BY-SA 4.0