Let M$M$ be an m$m$ dimensional differentiable manifold. Define Gauge(M):=C^{\infty}(M, Aut(TM))$\text{Gauge}(M) := \text{C}^∞(M, \text{Aut}(TM))$ to be the group of all (smooth) fiberwise linear transformations of the tangent bundle. This is the natural gauge group of the manifold. If (U, x_1,...,x_m)$\left(U, x_1,…,x_m\right)$ is a local coordinate system with induced frame on TU$TU$ then an element of Gauge(U)$\text{Gauge}(U)$ looks like an invetableinvertible matrix g_{ij}(x_1,...,x_m) $g_{ij}\left(x_1,…,x_m\right)$ (with i,j=1,...,m$i,j=1,…,m$) depending smoothly on the point. If
If we take a diffeomorphism of M$M$ interpreted as a coordinate transformation i.e., taking (U,x_1,...,x_m)$\left(U,x_1,…,x_m\right)$ into (U,y_1,...,y_m)$\left(U,y_1,…,y_m\right)$ with y_i(x_1,...,x_m) $y_i\left(x_1,…,x_m\right)$ (with i=1,...,m$i=1,…,m$) smooth functions then the corresponding Jacobi matrix gives rise to an element of Gauge(U)$\text{Gauge}(U)$ by putting locally g_{ij}(x_1,...,x_m):=dy_i/dx_j.$$g_{ij}\left(x_1,…,x_m\right) := \frac{dy_i}{dx_j}.$$
Hence among gauge transformations there are those which stem from a diffeomorphism hence we get a natural embedding Diff(M) < Gauge(M)$\text{Diff}(M) < \text{Gauge}(M)$.
The question is: (after appropriate topologies considered) can we say something about the quotient Gauge(M)/Diff(M)$\text{Gauge}(M)/\text{Diff}(M)$ i.e., in what extent is the gauge group "bigger"“bigger” than the diffeomorhism group of a manifold?
I would expect that the answer splits into a local answer and then a global one (involving the topology of M$M$).
The motivation comes from Kodaira-Spencer deformation theory of complex structures. In this theory two almost complex operators are considered to be equivalent if they differ by a diffeomorphism. However apparently gauge equivalence would be also a natural equivalence relation. Is this beacausebecause simply Kodaira-Spencer theory historically preceded gauge theory?
Thanks!