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Jul 15, 2021 at 5:55 comment added Watson Update: this question and the answer below gave rise to the following preprint arxiv.org/abs/2107.06432 :-)
May 25, 2021 at 13:58 vote accept Watson
May 24, 2021 at 19:37 comment added Watson @HYL : thanks! In fact, Example 5.19 therein gives an example of two geometrically simple abelian varieties of dimension 3 over $\Bbb F_2$ (lmfdb.org/Variety/Abelian/Fq/3/2/a_c_c, lmfdb.org/Variety/Abelian/Fq/3/2/d_f_h), which are not isogenous, but according to the LMFDB "All geometric endomorphisms are defined over $\Bbb F_{2}$" (namely the geometric endomorphism algebra is a CM number field of degree 6, lmfdb.org/NumberField/6.0.679024.1)
May 24, 2021 at 15:37 answer added Yuri Zarhin timeline score: 9
May 23, 2021 at 17:35 history became hot network question
May 23, 2021 at 16:29 vote accept Watson
May 24, 2021 at 16:10
May 23, 2021 at 13:34 answer added user166831 timeline score: 5
May 23, 2021 at 13:09 comment added HYL There are examples of abelian varieties with isomorphic endomorphism algebras but different $p$-ranks (see e.g. arxiv.org/pdf/2003.05380.pdf, §5.6) and $p$-ranks are isogenous invariants. If they still have the same endomorphism algebras over $\bar{k}$, they will provide counter-examples.
May 23, 2021 at 11:41 comment added Watson @Wojowu : Tate proved that any abelian variety over a finite field is a CM abelian variety (Prop. 16.27 in Moonen--Geer notes on Abelian Varieties).
May 23, 2021 at 11:33 comment added Wojowu Did you mean to assume $A_i$ have CM?
May 23, 2021 at 11:00 history edited YCor CC BY-SA 4.0
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May 23, 2021 at 9:29 history asked Watson CC BY-SA 4.0