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May 24, 2021 at 0:36 comment added Nick @JoeSilverman No, I do not want to assume they are polynomials. And What you wrote is (almost) $R_1 \circ R_2$, but I think you forgot an extra $-x$ in the first component. It doesn't matter that much, but I want to look at $R_2 \circ R_1$ (the horizontal reflection comes first), so it would be $$F(x,y) = \left( 2f_1(y)-x, 2f_2(2f_1(y)-x) - y \right)$$
May 23, 2021 at 7:14 history edited YCor CC BY-SA 4.0
removed capitals from title
May 23, 2021 at 1:23 comment added Joe Silverman So just to make sure I understand what you're asking, let $f_1(x)$ and $f_2(x)$ be functions. (Are they supposed be be polynomials?) Then you are looking at the dynamics of the map $$ F(x,y) = \Bigl( 2f_2\bigl(f_1(x)-y\bigr),2f_1(x)-y\Bigr). $$
May 22, 2021 at 23:33 history edited LSpice CC BY-SA 4.0
Name of "HERE"
May 22, 2021 at 23:27 history asked Nick CC BY-SA 4.0