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May 20, 2021 at 16:08 history edited leo monsaingeon
added the optimal-transportation tag
May 20, 2021 at 6:21 answer added leo monsaingeon timeline score: 1
May 19, 2021 at 20:13 comment added leo monsaingeon I see... then I suspect this is really tricky, getting sharp constants for such highly nonlinear functional inequalities can be delicate. One last comment, though: in the Euclidean setting the $\beta/2$ factor is related to displacement convexity (in the sense of McCann) of the relative entropy $\rho\mapsto H(\rho|\pi)$, which in turn is related to log-concavity of the reference measure $\pi$. There are results about displacement convexity over manifolds, in which case the Ricci curvature plays a significant role. Perhaps it's worth looking into it? (I recommend Villani's "big book")
May 19, 2021 at 20:09 comment added user_qj Thanks yes I understand the comment - but don't really want to reduce to the Euclidean setting in the bound :(
May 19, 2021 at 19:55 comment added leo monsaingeon Well, certainly if your Riemannian metric tensor $G(x)$ is uniformly bounded from below and from above you will get a similar inequality by paying a factor $C\approx (\lambda/\Lambda)^2$ or $C\approx (\Lambda/\lambda)^2$ in front of $\frac\beta 2$, where $\lambda\succ G(x)\succ \Lambda$ are the lower and upper bounds. In other words you can use the fact that the inequality holds true in the Euclidean setting. But perhaps you are really interested in the sharp $\frac{\beta}{2}$ factor? (in which case I don't know the answer, but I suspect this is actually not trivial at all)
May 19, 2021 at 18:22 history edited user_qj
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May 19, 2021 at 18:14 history edited user_qj
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May 19, 2021 at 18:08 review First posts
May 19, 2021 at 18:33
May 19, 2021 at 18:06 history asked user_qj CC BY-SA 4.0