Timeline for Looking for a $q$-analogue of a binomial identity
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| May 19, 2021 at 17:15 | vote | accept | T. Amdeberhan | ||
| May 18, 2021 at 22:29 | history | edited | T. Amdeberhan | CC BY-SA 4.0 |
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| May 18, 2021 at 22:03 | answer | added | Fedor Petrov | timeline score: 4 | |
| May 18, 2021 at 21:38 | history | edited | T. Amdeberhan | CC BY-SA 4.0 |
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| May 18, 2021 at 19:56 | comment | added | Sam Hopkins | Yes, I have no idea about, maybe I am just restating your problem. Of course you can try to find an expression for $\sum_{k\geq 0} \binom{2k}{k}_q x^k$, the usual q-binomial... | |
| May 18, 2021 at 19:55 | comment | added | T. Amdeberhan | You're right and I was aware of too. But, what would be the $q$-analogue g.f.? | |
| May 18, 2021 at 19:53 | comment | added | Sam Hopkins | The identity is essentially equivalent to the g.f. identity $\sum_{k \geq 0} \binom{2k}{k} x^k = 1/\sqrt{1-4x}$, so if you have a q-analog of that g.f. you'll get what you want. | |
| May 18, 2021 at 19:50 | history | edited | F. C. |
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| May 18, 2021 at 19:45 | history | asked | T. Amdeberhan | CC BY-SA 4.0 |