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May 24, 2021 at 6:41 comment added YCor I assume $p$-Lie algebra means Lie algebra in which the underlying additive group is a $p$-group, for prime $p$. In this case, if $p\neq 3$ and if every 2-generator subalgebra is 2-nilpotent, then it's 2-nilpotent. Indeed, writing $[x,[y,z]]=xyz$, the condition $xxz=0$ for all $x,z$ implies $xyz+yxz=0$ for all $x,y,z$, so $xyz=yzx$, and then by Jacobi, $3xyz=0$, hence $xyz=0$.
May 24, 2021 at 3:09 history edited LSpice CC BY-SA 4.0
k -> $k$
May 24, 2021 at 2:00 answer added Alireza Abdollahi timeline score: 2
May 18, 2021 at 15:46 history asked Joshua Grochow CC BY-SA 4.0