Skip to main content
10 events
when toggle format what by license comment
May 18, 2021 at 21:15 history closed Gro-Tsen
abx
Christian Remling
Andreas Blass
leo monsaingeon
Not suitable for this site
May 15, 2021 at 19:13 vote accept Zaragosa
May 15, 2021 at 14:12 answer added Gerald Edgar timeline score: 1
May 15, 2021 at 7:12 history edited Zaragosa
edited tags
May 15, 2021 at 7:02 comment added Zaragosa @NateEldredge for the number 2. In the number 1 I found an error, actually I need to prove only this $f_\epsilon(z)\neq a$.
May 15, 2021 at 6:59 history edited Zaragosa CC BY-SA 4.0
added 16 characters in body
May 15, 2021 at 0:45 comment added Nate Eldredge #1 looks fine to me. The boundedness is only needed if you want $f_\epsilon$ to end up being real-valued, and even then you would only need $f$ bounded below. If you allow $f_\epsilon$ to take the value $-\infty$ then it works for unbounded functions too.
May 15, 2021 at 0:15 review Close votes
May 18, 2021 at 21:15
May 15, 2021 at 0:13 comment added Nate Eldredge For 2, note that for each $x$, $f_\epsilon(x)$ increases as $\epsilon \downarrow 0$, so you can just take the sup over $f_{1/n}(x)$, $n=1,2,3,\dots$. Then it's a sup of a countable set of functions and you are in business.
May 14, 2021 at 23:42 history asked Zaragosa CC BY-SA 4.0