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May 15, 2021 at 8:03 comment added Kolodez Maybe it is not closed. But I am only interested in approximating semimartingales.
May 15, 2021 at 8:02 comment added Kolodez This definition of $\mathcal S$ is where my problem comes from. After that, I needed to find a fitting title. :)
May 14, 2021 at 23:46 comment added Nate Eldredge Is the class of semimartingales actually closed under $L^2(\Omega \times [0,T])$ convergence? That's not a property I remember.
May 14, 2021 at 22:10 comment added Nate River If you want to emulate the definition of absolutely continuous for processes, wouldn’t it make sense to take $Y_t$ to be almost surely $L^1$ in time, instead of the stronger continuous and bounded?
May 14, 2021 at 21:16 history asked Kolodez CC BY-SA 4.0