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May 12, 2021 at 12:04 comment added Benjamin Steinberg @Student this is the same counterexample I have in my answer but I didn't put the proof
May 12, 2021 at 3:22 comment added Student This is also known as the failure of the Schur's lemma in uncountable dimensions - see this with a proof in the countable case and a counter-proof in the uncountable case.
May 9, 2021 at 20:56 history made wiki Post Made Community Wiki by Stefan Kohl
May 9, 2021 at 20:46 comment added Benjamin Steinberg Yes. It is really about the algebra having smaller dimension than the cardinality of the field
May 9, 2021 at 20:39 comment added YCor So eventually the point is that every field extension of an algebraically closed field of infinite cardinal $\alpha$ has dimension $\ge\alpha$.
May 9, 2021 at 20:34 history answered Benjamin Steinberg CC BY-SA 4.0