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May 11, 2021 at 17:44 comment added Arno Fehm @Wojowu: Indeed, these are very natural questions, but as far as I am aware it's not known. The standard proof applied to a field of cardinality $\kappa$ just gives that the set of such $\sigma$ is an intersection of $\kappa$ many sets of measure 1 (one for each geometrically irreducible variety).
May 11, 2021 at 14:30 comment added Wojowu Nonmeasurable, what a twist! Do we know if this set can have a well-defined measure smaller than 1? Maybe even equal to 0?
May 9, 2021 at 20:56 history made wiki Post Made Community Wiki by Stefan Kohl
May 9, 2021 at 20:27 history answered Arno Fehm CC BY-SA 4.0