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For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A, \mathbb{F}_p)=\emptyset?$$Do all the finite $P$ arise this way?
$A=\mathbb{Z}/n$ works for the cofinite $P$.
For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A, \mathbb{F}_p)=\emptyset?$$
$A=\mathbb{Z}/n$ works for the cofinite $P$.
For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A, \mathbb{F}_p)=\emptyset?$$Do all the finite $P$ arise this way?
Set of primes $p$ such that $\mathrm{Hom}(A\otimes \mathbb{F}_pA, \mathbb{F}_p)=\emptyset$
For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A\otimes \mathbb{F}_p, \mathbb{F}_p)=\emptyset?$$$$p\in P\iff\mathrm{Hom}(A, \mathbb{F}_p)=\emptyset?$$
$A=\mathbb{Z}/n$ works for the cofinite $P$.
Set of primes $p$ such that $\mathrm{Hom}(A\otimes \mathbb{F}_p, \mathbb{F}_p)=\emptyset$
For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A\otimes \mathbb{F}_p, \mathbb{F}_p)=\emptyset?$$
$A=\mathbb{Z}/n$ works for the cofinite $P$.
Set of primes $p$ such that $\mathrm{Hom}(A, \mathbb{F}_p)=\emptyset$
For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A, \mathbb{F}_p)=\emptyset?$$
For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A\otimes \mathbb{F}_p, \mathbb{F}_p)=\emptyset?$$
$A=\mathbb{Z}/n$ works for the cofinite $P$.
For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A\otimes \mathbb{F}_p, \mathbb{F}_p)=\emptyset?$$
For which sets of primes $P$ is there a finite type $\mathbb{Z}$-algebra $A$ such that$$p\in P\iff\mathrm{Hom}(A\otimes \mathbb{F}_p, \mathbb{F}_p)=\emptyset?$$
