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May 14, 2021 at 1:07 vote accept Shiyu
May 10, 2021 at 11:58 comment added Jukka Kohonen I believe the new question (on a sphere) is sufficiently different that it would be better asked in a separate question.
May 10, 2021 at 9:25 answer added Fedor Petrov timeline score: 3
May 10, 2021 at 9:09 comment added Alapan Das @Fedor Petrov, oh, I see. Thank you for correcting me. I had mistakenly assumed the barycentre at 0 as the points making regular $n$-gon on the sphere.
May 10, 2021 at 8:49 comment added Fedor Petrov @AlapanDas not only, it happens when they are on the circle and 0 is barycentre
May 10, 2021 at 8:23 history edited Shiyu CC BY-SA 4.0
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May 10, 2021 at 5:11 history edited YCor
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May 9, 2021 at 15:45 comment added Alapan Das For, $a=2$, $J=n\sum_{i}r_i^2 -[S_x^2+S_y^2+S_3^2]$ where, $r_i$ is the distance from the origin and $S_{x,y,z}=\sum_{i} \{x,y,z\}_i$. Hence, it will be maximum iff $(S_x,S_y,S_z)=\vec{0}$ and distances are maximum possible. This happens only when all the points are on the circle and forms a regular $n$-gon.
May 9, 2021 at 1:34 review First posts
May 9, 2021 at 5:52
May 9, 2021 at 1:21 history asked Shiyu CC BY-SA 4.0