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May 6, 2021 at 17:07 vote accept Nicole
May 5, 2021 at 19:08 history edited Fedor Petrov CC BY-SA 4.0
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May 5, 2021 at 16:09 comment added Nicole Yes, you are right. While I was trying to say was that this $H$ matrix is fixed with eigenvalues less than $\ell$, and after we have such an $H$ we then try to find constants $\mu$ and $\rho$.
May 5, 2021 at 15:59 comment added Fedor Petrov Well, but if it is given, why to say that its eigenvalues are bounded? Any finite set is bounded.
May 5, 2021 at 15:43 comment added Nicole Hi, thanks for your example. But I am sorry that I didn't make it clear. Here H is a fixed symmetric matrix meaning that it is fixed before we choose $\mu$. While in your example, $H$ changes with $\mu$.
May 5, 2021 at 15:29 history answered Fedor Petrov CC BY-SA 4.0