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May 5, 2021 at 15:22 comment added xir okay, thanks for your help! :)
May 5, 2021 at 7:31 comment added Dmitry Vaintrob Right, this is true on the nose in the cancellative case only. In the non-cancellative case this is true in a derived sense, if you define the localization in an infinity-categorical sense. (See e.g. ncatlab.org/nlab/show/group+completion or the Dwyer-Kan paper referenced there.)
May 5, 2021 at 4:08 comment added xir this is true even in the non-cancellative case, right? it's basically the discrete version of the group completion theorem. I was slightly confused about this point because of Benjamin's comment below about classifying space and derived functor giving the same cohomology, which maybe maybe also only applies in the non-cancellative case, since it seems to me like group completion can change the derived functor construction but not the classifying space one.
May 5, 2021 at 0:31 comment added Dmitry Vaintrob I see. That will actually always be equivalent to the classifying space for the group completion, essentially since the classifying space construction doesn't distinguish "forwards" and "backwards" arrows
May 5, 2021 at 0:08 comment added xir i meant the cohomology of the space BM (the classifying space construction, which applies to a general category, including the one-object category M).
May 5, 2021 at 0:08 comment added xir oh that's really dumb of me haha, thank you! for some unfathomable reason i was convinced A also had to be supported there.
May 4, 2021 at 22:53 comment added Dmitry Vaintrob The cohomology Ext_M(Z,A) most certainly is computable by pullback to the group completion! The module Z is supported in the open Z[M^{gp}], and so any Ext can be computed after localizing to this open. By "same as the categorical cohomology" I mean it is the same as the cohomology of the trivial representation of the corresponding category (not sure if this is what you mean by "classifying space as a category")
May 4, 2021 at 22:42 comment added xir I'm not sure how to use it to compute an actual specific group of this sort though. also, by "the same as the categorical cohomology," what do you mean?
May 4, 2021 at 22:41 comment added xir I mostly asked because I was just curious, but the original use case I had was figuring out something about Ext_M(Z, A) for commutative cancellative M and a certain non-trivial module A which definitely can't be computed via pullback to the group completion. and yeah that geometric picture seems very interesting and promising to me.
May 4, 2021 at 22:39 vote accept xir
May 4, 2021 at 22:09 comment added Dmitry Vaintrob Maybe more generally, a very good first thing to do when working with a commutative monoid M is to pass to the corresponding "toric" geometry object X = Spec Z[M]. The category of M-representations is equivalent to the category of quasicoherent sheaves on X, and invariants computed in this category have geometric meaning. If you want to encode the Hopf algebra of M and not just its underlying ring, this is equivalent to considering its spectrum X as a semigroup object. Most interesting monoid invariants should have meaning as invariants of commutative geometric semigroups.
May 4, 2021 at 21:56 comment added Dmitry Vaintrob What is the use case that you have in mind? The most straightforward generalization of group cohomology would be Ext_M(Z, Z) which is the same as the categorical cohomology. The problem is that this is a boring invariant in the commutative cancellative case since it is invariant under group completion. Indeed, transposing to geometry, this is the self-Ext of the skyscraper sheaf at 1 in Spec(Z[M]), which can be computed inside the open chart Spec(Z[M^gp]) corresponding to the group completion.
May 4, 2021 at 18:35 answer added Benjamin Steinberg timeline score: 2
May 4, 2021 at 16:41 history asked xir CC BY-SA 4.0