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May 24, 2021 at 2:26 comment added Jesse Elliott I now think the continued fraction actually diverges for $x > 1$, but I don't know how to prove this.
May 16, 2021 at 20:58 history edited Jesse Elliott CC BY-SA 4.0
The expansions in the references are not known to be valid on the domain sought in the original post.
May 5, 2021 at 20:50 comment added Jesse Elliott Again, (3.3.10) holds only for $|\operatorname{arg}(-\operatorname{Ln}(z)| < \pi$, which excludes the domain $x > 1$. Do you see the issue here?
May 3, 2021 at 20:44 comment added Jesse Elliott This won't do it. The expansion for $\operatorname{Ei}(-z)$ is proved valid only for $|\operatorname{arg}(z)| < \pi$ and the expansion for $\operatorname{li}(z)$ for $|\operatorname{arg}(-\operatorname{Ln}(z))|< \pi$, which rules out the domain of $x > 1$ for $\operatorname{li}(x)$ that I'm interested in. (I actually have a copy of the book.)
May 3, 2021 at 14:50 comment added LSpice The PDF link goes to the freely available "Back matter" of the Springer (re-?)issue of the referenced book. Here's a DOI link to the book: Lorentzen and Waadeland - Continued fractions - I.
May 3, 2021 at 5:53 history answered Alexey Ustinov CC BY-SA 4.0