One part of your question asks for naturally occuring categories (which are triangulated, presumably, since triangulated categories are the categorical setting for earlier parts of the question) whichwhose $K_0$-groups are vector spaces over finite fields.
One source of such triangulated categories is stable module categories of quasi-Frobenius rings. Recall that the "stable module category" of a ring $R$ has, as objects, the $R$-modules, and as morphisms from $M$ to $N$, the set of equivalence classes of $R$-module morphisms $M\rightarrow N$, where two morphisms are said to be equivalent if their difference factors through a projective $R$-module. Recall also that a ring is "quasi-Frobenius" if its projective modules coincide with its injective modules. The stable module category of a quasi-Frobenius ring $R$ has a natural triangulation; I will write $stMod(R)$ for that triangulated category, restricted to its finitely generated modules, in order to avoid an Eilenberg swindle argument which would cause $K_0$ to vanish.
Consider the example $R = \mathbb{Z}/4\mathbb{Z}$. Every finitely-generated $R$-module is a direct sum of copies of $\mathbb{Z}/2\mathbb{Z}$ and $P = \mathbb{Z}/4\mathbb{Z}$, and $P$ is zero in the stable module category of $R$. Hence $K_0(stMod(R))$ must be a cyclic group generated by $[\mathbb{Z}/2\mathbb{Z}]$. However, we have the short exact sequence $$ 0 \rightarrow \mathbb{Z}/2\mathbb{Z}\rightarrow P \rightarrow \mathbb{Z}/2\mathbb{Z} \rightarrow 0$$ of $R$-modules, and consequently $[\mathbb{Z}/2\mathbb{Z}] + [\mathbb{Z}/2\mathbb{Z}] = [P] = 0$ in $K_0(stMod(R))$. So we have $K_0(stMod(R)) \cong \mathbb{Z}/2\mathbb{Z}$.
By a similar argument, for any prime $p$ and any positive integer $n$, we have $K_0(stMod(\mathbb{Z}/p^n\mathbb{Z})) \cong \mathbb{Z}/n\mathbb{Z}$. We also have $K_0(stMod(k[x]/x^n)) \cong \mathbb{Z}/n\mathbb{Z}$ for any field $k$. All that is really necessary for these kinds of $K_0$ calculations is that the ring $R$ be quasi-Frobenius, so that its stable module category is triangulated, and that $R$ is an Artinian principal ideal ring, so that its modules are all direct sums of cyclics.
Consequently, if $p$ is a prime and you want to recover $\mathbb{F}_p^n$ as $K_0$ of a triangulated category, then the triangulated category $stMod(R)$ will work, where $R$ is a Cartesian product of $n$ copies of $\mathbb{Z}/\ell^p\mathbb{Z}$ for any prime $\ell$ (or, alternatively, $n$ copies of $k[x]/x^p$ for any field $k$).
You also ask about constructing triangulated categories whose $K_0$ is a vector space over, for example, the rational numbers. This is much more difficult than the finite field case. It is a nontrivial task to construct a triangulated category whose $K_0$ is $\mathbb{Q}$, or even just $\mathbb{Z}[\frac{1}{2}]$; this is tied up in the general problem of figuring out how to modify a given triangulated category so that a prime becomes inverted in its $K_0$. The papers https://arxiv.org/abs/1610.07162 and https://arxiv.org/abs/1702.07466 are about this problem, and you can find positive results specifically about the $\mathbb{Q}$ case of your problem in the Barwick-Glasman-Hoyois-Nardin-Shah paper (the first arXiv link).