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May 1, 2021 at 16:52 vote accept Tomer
May 1, 2021 at 14:07 history edited Gerald Edgar CC BY-SA 4.0
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May 1, 2021 at 13:58 comment added abx @მამუკა ჯიბლაძე: One can also say that $C$ is compact because it is the (continuous) image of $\prod [-2^{-k},2^k]$. And if its interior were non-empty, the closed unit ball would be compact.
May 1, 2021 at 13:08 comment added მამუკა ჯიბლაძე Also I believe $C$ is not contained in any hyperplane, no?
May 1, 2021 at 13:06 comment added მამუკა ჯიბლაძე For lamers like me who do not see immediately why is $C$ compact and why compactness implies empty interior: to find a point outside $C$ arbitrarily close to any given $x_*\in C$, replace one of the $x_k$ with $x_k+2^{2-k}$ (and leave all other $x$es intact).
May 1, 2021 at 11:31 history answered Gerald Edgar CC BY-SA 4.0