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Apr 30, 2021 at 17:41 review Close votes
May 15, 2021 at 3:08
Apr 30, 2021 at 17:32 comment added Ma Joad @Kostya_I I mean, we can include some information $T$ and combine it with the result above.
Apr 30, 2021 at 17:31 comment added Kostya_I The moment generating function of $S_T$ uniquely determines the distribution of $S_T$, so obviously it cannot be determined uniquely without using some information about how $T$ is defined. Moreover, if it were Brownian motion not RW, then Skorokhod's embedding theorem says that $S_T$ can be distributed in arbitrary way (say, with finite second moment).
Apr 30, 2021 at 16:17 history asked Ma Joad CC BY-SA 4.0