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Sep 17, 2010 at 21:06 history edited Joseph O'Rourke CC BY-SA 2.5
added 17 characters in body
Sep 17, 2010 at 21:05 comment added Joseph O'Rourke @Ellipsissi: Apologies! So the radius is as per Sergei's correction.
Sep 17, 2010 at 20:43 comment added Ellipsissi Yes, the meaning is that p1 is on the circle, not in the disk. Thank you for your help.
Sep 17, 2010 at 20:26 history edited Joseph O'Rourke CC BY-SA 2.5
Sergei correction.; added 39 characters in body
Sep 17, 2010 at 20:24 comment added Joseph O'Rourke @Sergei: Hmmm. If, say, $r_1=10$ and $D=1$, then it seems one obtains a disk of radius 11, rather than an annulus with inner radius $|1-10|=9$? Ah, maybe we are interpreting $p_1 \in C_1$ differently. I was interpreting it as $p_1$ inside the circle, but I see that may be a mistaken assumption. If it means $p_1$ on the circle, then you are correct.
Sep 17, 2010 at 20:10 comment added Sergei Ivanov The inner radius should be $|D-r_1|$.
Sep 17, 2010 at 19:52 vote accept Ellipsissi
Sep 17, 2010 at 19:53
Sep 17, 2010 at 19:39 history answered Joseph O'Rourke CC BY-SA 2.5