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Jul 6, 2021 at 8:01 comment added ntessore There is, as far as I can tell, absolutely nothing special about the spherical harmonic expansion of $f^3$ for a spherical function $f$ over $S^2$.
S May 6, 2021 at 16:05 history bounty ended CommunityBot
S May 6, 2021 at 16:05 history notice removed CommunityBot
Apr 29, 2021 at 16:11 comment added user4164 @Carlo Beenakker: Yes, this is what I am getting, but I am not satisfied with the n-th fold convolution...
Apr 28, 2021 at 17:06 comment added Carlo Beenakker this would amount to an $n$-fold convolution of the expansion coefficients of $f$, I don't see how anything simpler would appear.
Apr 28, 2021 at 17:01 history edited YCor CC BY-SA 4.0
removed capitals from title
Apr 28, 2021 at 16:13 comment added user4164 @Michael Engelhard: I would like to find coefficients of $f^n$ in terms of coefficients of $f$, i.e their relation.
Apr 28, 2021 at 16:12 history edited user4164 CC BY-SA 4.0
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Apr 28, 2021 at 16:06 comment added user4164 @Carlo Beenakker: Yes, I would like to find a coefficients of the expansion of $f^n$, in particular their relation with the expansion of $f$. Will add this to the question. Thank you.
Apr 28, 2021 at 15:51 comment added Michael Engelhardt Would the answer $c_{l,i} = \langle Y_{l,i} | f^n \rangle $ satisfy you, and why not?
Apr 28, 2021 at 15:24 comment added Carlo Beenakker perhaps you can give some more info? do you want a relation between the expansion coefficients of $f^n$ and those of $f$?
S Apr 28, 2021 at 14:19 history bounty started user4164
S Apr 28, 2021 at 14:19 history notice added user4164 Canonical answer required
Apr 26, 2021 at 13:38 history asked user4164 CC BY-SA 4.0