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Luka Thaler
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This is a difficult problem and I don't think that we are getting any closer to its solution. I think there is no hope of finding an explicit automorphism that would map both axis to themselves and which would have an attracting fixed point somewhere outside the axis.

There are other ways people have tried to tackle this problem, for example by trying to find an automorphism with a parabolic, semiparabolic, quasiparabolic or resonant fixed point at the origin whose attracting domain (fatou component) avoids both axis. Now most of these domains are known to be biholomorphic to $\mathbb C^2$, but in the resonant case you could also have $\mathbb C \times \mathbb C^*$ [Bracci, F., J. Raissy, and B. Stensønes. “Automorphisms of $\mathbb C^k$ with an invariant non-recurrentattracting Fatou component biholomorphic to $\mathbb C \times (\mathbb C^*)^{k-1}$.”J. Eur. Math. Soc.(2020)]. If I recall correctly in their case the domain almost avoided both axis. Note that if you manage to find a domain that is biholomorphic to $\mathbb C \times \mathbb C^*$ and which avoids both axis then you have solved the problem. This follows from the fact that $\mathbb C \times \mathbb C^*$ has the density property therefore if in there you can find a copy of $\mathbb C^2$. Finally another keyword for you would be a parabolic cylinder.

This is a difficult problem and I don't think that we are getting any closer to its solution. I think there is no hope of finding an explicit automorphism that would map both axis to themselves and which would have an attracting fixed point somewhere outside the axis.

There are other ways people have tried to tackle this problem, for example by trying to find an automorphism with a parabolic, semiparabolic, quasiparabolic or resonant fixed point at the origin whose attracting domain (fatou component) avoids both axis. Now most of these domains are known to be biholomorphic to $\mathbb C^2$, but in the resonant case you could also have $\mathbb C \times \mathbb C^*$ [Bracci, F., J. Raissy, and B. Stensønes. “Automorphisms of $\mathbb C^k$ with an invariant non-recurrentattracting Fatou component biholomorphic to $\mathbb C \times (\mathbb C^*)^{k-1}$.”J. Eur. Math. Soc.(2020)]. If recall correctly in their case the domain almost avoided both axis. Note that if you manage to find a domain that is biholomorphic to $\mathbb C \times \mathbb C^*$ and which avoids both axis then you have solved the problem. This follows from the fact that $\mathbb C \times \mathbb C^*$ has the density property therefore if in there you can find a copy of $\mathbb C^2$. Finally another keyword for you would be a parabolic cylinder.

This is a difficult problem and I don't think that we are getting any closer to its solution. I think there is no hope of finding an explicit automorphism that would map both axis to themselves and which would have an attracting fixed point somewhere outside the axis.

There are other ways people have tried to tackle this problem, for example by trying to find an automorphism with a parabolic, semiparabolic, quasiparabolic or resonant fixed point at the origin whose attracting domain (fatou component) avoids both axis. Now most of these domains are known to be biholomorphic to $\mathbb C^2$, but in the resonant case you could also have $\mathbb C \times \mathbb C^*$ [Bracci, F., J. Raissy, and B. Stensønes. “Automorphisms of $\mathbb C^k$ with an invariant non-recurrentattracting Fatou component biholomorphic to $\mathbb C \times (\mathbb C^*)^{k-1}$.”J. Eur. Math. Soc.(2020)]. If I recall correctly in their case the domain almost avoided both axis. Note that if you manage to find a domain that is biholomorphic to $\mathbb C \times \mathbb C^*$ and which avoids both axis then you have solved the problem. This follows from the fact that $\mathbb C \times \mathbb C^*$ has the density property therefore if in there you can find a copy of $\mathbb C^2$. Finally another keyword for you would be a parabolic cylinder.

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Luka Thaler
  • 589
  • 5
  • 15

This is a difficult problem and I don't think that we are getting any closer to its solution. I think there is no hope of finding an explicit automorphism that would map both axis to themselves and which would have an attracting fixed point somewhere outside the axis.

There are other ways people have tried to tackle this problem, for example by trying to find an automorphism with a parabolic, semiparabolic, quasiparabolic or resonant fixed point at the origin whose attracting domain (fatou component) avoids both axis. Now most of these domains are known to be biholomorphic to $\mathbb C^2$, but in the resonant case you could also have $\mathbb C \times \mathbb C^*$ [Bracci, F., J. Raissy, and B. Stensønes. “Automorphisms of $\mathbb C^k$ with an invariant non-recurrentattracting Fatou component biholomorphic to $\mathbb C \times (\mathbb C^*)^{k-1}$.”J. Eur. Math. Soc.(2020)]. If recall correctly in their case the domain almost avoided both axis. Note that if you manage to find a domain that is biholomorphic to $\mathbb C \times \mathbb C^*$ and which avoids both axis then you have solved the problem. This follows from the fact that $\mathbb C \times \mathbb C^*$ has the density property therefore if in there you can find a copy of $\mathbb C^2$. Finally another keyword for you would be a parabolic cylinder.