Skip to main content
Post Closed as "Not suitable for this site" by Neil Strickland, Ben McKay, Tim Campion
Corrected grammar.
Source Link
Tim Campion
  • 63.9k
  • 13
  • 143
  • 384

Is Does this calculus has exact valueintegral have a closed form solution?

Let $x,y\in \mathbb{R}^2$, $B_r(0)=\{x||x|\leq r\}$. So doesDoes the following calculusfunction (denoted as $f(r)$) have exacta closed form expression?

$$f(r)=\int_{B_r(0)}\int_{B_r(0)}\ln|x-y|dxdy.$$

Is this calculus has exact value?

Let $x,y\in \mathbb{R}^2$, $B_r(0)=\{x||x|\leq r\}$. So does the following calculus(denoted as $f(r)$) have exact expression?

$$f(r)=\int_{B_r(0)}\int_{B_r(0)}\ln|x-y|dxdy.$$

Does this integral have a closed form solution?

Let $x,y\in \mathbb{R}^2$, $B_r(0)=\{x||x|\leq r\}$. Does the following function (denoted as $f(r)$) have a closed form expression?

$$f(r)=\int_{B_r(0)}\int_{B_r(0)}\ln|x-y|dxdy.$$

Source Link
W.J.
  • 379
  • 1
  • 6

Is this calculus has exact value?

Let $x,y\in \mathbb{R}^2$, $B_r(0)=\{x||x|\leq r\}$. So does the following calculus(denoted as $f(r)$) have exact expression?

$$f(r)=\int_{B_r(0)}\int_{B_r(0)}\ln|x-y|dxdy.$$