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Jun 15, 2021 at 14:51 comment added Daniel Adams It is no surprise that the stationary distribution puts more mass around the minimisers of $U$ ( since the particle drifts towards such minimisers).
Apr 26, 2021 at 4:10 vote accept Linus Hamilton
Apr 24, 2021 at 8:05 answer added Nawaf Bou-Rabee timeline score: 9
Apr 24, 2021 at 7:59 answer added Abhishek Halder timeline score: 5
Apr 24, 2021 at 7:09 history edited YCor CC BY-SA 4.0
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Apr 23, 2021 at 23:18 comment added pupshaw perhaps you would consider this only a case of miraculous second-order cancellation, but you can see the stationarity in a more pathwise way via Itô's formula. But I hope you get a better answer than this.
Apr 23, 2021 at 20:53 comment added Carlo Beenakker The long-time limit is the equilibrium distribution, which is the Maxwell-Boltzmann distribution $e^{-U/kT}$ --- in the units you are using $kT$ equals 1.
Apr 23, 2021 at 20:40 history asked Linus Hamilton CC BY-SA 4.0