Timeline for Oscillating sums
Current License: CC BY-SA 4.0
9 events
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Apr 21, 2021 at 14:48 | history | edited | coco | CC BY-SA 4.0 |
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Apr 21, 2021 at 14:34 | comment | added | username | If the constant $c$ is independent of $\epsilon$, then it should be true for all $\epsilon$. Indeed, given $\epsilon>0$, just take $f(n)= \sum_{k=0}^n a_k \sin (k\epsilon)$. | |
Apr 21, 2021 at 14:31 | answer | added | Iosif Pinelis | timeline score: 3 | |
Apr 21, 2021 at 14:28 | comment | added | coco | For a specific $\epsilon\in(0,1)$. | |
Apr 21, 2021 at 14:26 | comment | added | username | Do you mean: Assume that there is a function $f$ such that for all $n>0$ and all $\epsilon\in(0,1)$, $$\sum_{k=0}^n a_k \sin (k\epsilon) \geq f(n)$$ or do you mean that for a specific $\epsilon>0$, $$\sum_{k=0}^n a_k \sin (k\epsilon) \geq f(n)?$$ | |
Apr 21, 2021 at 14:18 | review | First posts | |||
Apr 21, 2021 at 14:40 | |||||
Apr 21, 2021 at 14:17 | history | edited | Francesco Polizzi | CC BY-SA 4.0 |
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Apr 21, 2021 at 14:16 | history | edited | coco | CC BY-SA 4.0 |
added 33 characters in body
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Apr 21, 2021 at 14:04 | history | asked | coco | CC BY-SA 4.0 |