This question iswas answered in commentsthe comments by fedja. Consider $$ f(t,v)=\min_s \sqrt{(X(s)-v)^2+(t-s)^2} $$$$ f(t,v)=\min_s \sqrt{(X(s)-v)^2+(t-s)^2}. $$ This function is Lipschitz, as the distance from $(t,v)$ to the graph of $X$. Whether or not $X$ has bounded variationsvariation, $f(t,X(t))$ is identically zero.