Skip to main content

Having had a quick look, does the following work? Put $x= \sum\_i x\_i/3$$x= \sum_i x_i/3$ and put

$$ y(t) = \sum\nolimits\_{i \in {R^1}_t} x_i = \sum\_i \eta\_i(t)x\_i $$

and $$ y(t) = \sum_{i \in R^1_t} x_i = \sum_i \eta_i(t)x_i $$ and try to substitute these into (3.2).

Observe that

$$ \begin{aligned} |x| + |y(t)| = | \frac13 \sum\_i x\_i | + | \sum\_i \eta\_i x\_i | & \leq | \frac13 \sum\_i x\_i | + | \sum\_i x\_i / 3 | + | \sum\_i (\eta\_i - 1/3)x\_i | \\\\ &\leq | \sum\_i x\_i | + | \sum\_i (\eta\_i - 1/3)x\_i | \end{aligned} $$

and $$ \begin{aligned} |x| + |y(t)| = | \frac13 \sum_i x_i | + | \sum_i \eta_i x_i | & \leq | \frac13 \sum_i x_i | + | \sum_i x_i / 3 | + | \sum_i (\eta_i - 1/3)x_i | \\ &\leq | \sum_i x_i | + | \sum_i (\eta_i - 1/3)x_i | \end{aligned} $$ and this should give what we want on the RHS of the formula you're asking about.

Having had a quick look, does the following work? Put $x= \sum\_i x\_i/3$ and put

$$ y(t) = \sum\nolimits\_{i \in {R^1}_t} x_i = \sum\_i \eta\_i(t)x\_i $$

and try to substitute these into (3.2).

Observe that

$$ \begin{aligned} |x| + |y(t)| = | \frac13 \sum\_i x\_i | + | \sum\_i \eta\_i x\_i | & \leq | \frac13 \sum\_i x\_i | + | \sum\_i x\_i / 3 | + | \sum\_i (\eta\_i - 1/3)x\_i | \\\\ &\leq | \sum\_i x\_i | + | \sum\_i (\eta\_i - 1/3)x\_i | \end{aligned} $$

and this should give what we want on the RHS of the formula you're asking about.

Having had a quick look, does the following work? Put $x= \sum_i x_i/3$ and put $$ y(t) = \sum_{i \in R^1_t} x_i = \sum_i \eta_i(t)x_i $$ and try to substitute these into (3.2).

Observe that $$ \begin{aligned} |x| + |y(t)| = | \frac13 \sum_i x_i | + | \sum_i \eta_i x_i | & \leq | \frac13 \sum_i x_i | + | \sum_i x_i / 3 | + | \sum_i (\eta_i - 1/3)x_i | \\ &\leq | \sum_i x_i | + | \sum_i (\eta_i - 1/3)x_i | \end{aligned} $$ and this should give what we want on the RHS of the formula you're asking about.

edited LaTeX
Source Link
Yemon Choi
  • 25.8k
  • 9
  • 69
  • 156

Having had a quick look, does the following work? Put x= (\sum_i x_i)/3$x= \sum\_i x\_i/3$ and put

y(t) = \sum_{i \in R^1_t} x_i = \sum_i \eta_i(t)x_i$$ y(t) = \sum\nolimits\_{i \in {R^1}_t} x_i = \sum\_i \eta\_i(t)x\_i $$

and try to substitute these into (3.2).

Observe that

|x| + |y(t)|

= | 1/3 \sum_i x_i | + | \sum_i \eta_i x_i |

\leq | 1/3 \sum_i x_i | + | \sum_i x_i / 3 | + | \sum_i (\eta_i - 1/3)x_i |

&\leq | \sum_i x_i | + | \sum_i (\eta_i - 1/3)x_i |$$ \begin{aligned} |x| + |y(t)| = | \frac13 \sum\_i x\_i | + | \sum\_i \eta\_i x\_i | & \leq | \frac13 \sum\_i x\_i | + | \sum\_i x\_i / 3 | + | \sum\_i (\eta\_i - 1/3)x\_i | \\\\ &\leq | \sum\_i x\_i | + | \sum\_i (\eta\_i - 1/3)x\_i | \end{aligned} $$

and this should give what we want on the RHS of the formula you're asking about.

Having had a quick look, does the following work? Put x= (\sum_i x_i)/3 and put

y(t) = \sum_{i \in R^1_t} x_i = \sum_i \eta_i(t)x_i

and try to substitute these into (3.2).

Observe that

|x| + |y(t)|

= | 1/3 \sum_i x_i | + | \sum_i \eta_i x_i |

\leq | 1/3 \sum_i x_i | + | \sum_i x_i / 3 | + | \sum_i (\eta_i - 1/3)x_i |

&\leq | \sum_i x_i | + | \sum_i (\eta_i - 1/3)x_i |

and this should give what we want on the RHS of the formula you're asking about.

Having had a quick look, does the following work? Put $x= \sum\_i x\_i/3$ and put

$$ y(t) = \sum\nolimits\_{i \in {R^1}_t} x_i = \sum\_i \eta\_i(t)x\_i $$

and try to substitute these into (3.2).

Observe that

$$ \begin{aligned} |x| + |y(t)| = | \frac13 \sum\_i x\_i | + | \sum\_i \eta\_i x\_i | & \leq | \frac13 \sum\_i x\_i | + | \sum\_i x\_i / 3 | + | \sum\_i (\eta\_i - 1/3)x\_i | \\\\ &\leq | \sum\_i x\_i | + | \sum\_i (\eta\_i - 1/3)x\_i | \end{aligned} $$

and this should give what we want on the RHS of the formula you're asking about.

typo cleaned up
Source Link
Yemon Choi
  • 25.8k
  • 9
  • 69
  • 156

Having had a quick look, does the following work? Put x= (\sum_i x_i)/3 and put

y(t) = \sum_{i \in R^1_t} x_i = \sum_i \eta_i(t)x_i

and try to substitute these into (3.2).

Observe that

|x| + |y(t)|

= | 1/3 \sum_i x_i | + | \sum_i \eta_i x_i |

\leq | 1/3 \sum_i x_i | + | \sum_i x_i / 3 | + | \sum_i (\eta_i - 1/3)x_i |

&\leq | \sum_i x_i | + | \sum_i (\eta_i - 1/3)x_i |

and this should give what we want on the RHS of the formula you're asking about. It sh

Having had a quick look, does the following work? Put x= (\sum_i x_i)/3 and put

y(t) = \sum_{i \in R^1_t} x_i = \sum_i \eta_i(t)x_i

and try to substitute these into (3.2).

Observe that

|x| + |y(t)|

= | 1/3 \sum_i x_i | + | \sum_i \eta_i x_i |

\leq | 1/3 \sum_i x_i | + | \sum_i x_i / 3 | + | \sum_i (\eta_i - 1/3)x_i |

&\leq | \sum_i x_i | + | \sum_i (\eta_i - 1/3)x_i |

and this should give what we want on the RHS of the formula you're asking about. It sh

Having had a quick look, does the following work? Put x= (\sum_i x_i)/3 and put

y(t) = \sum_{i \in R^1_t} x_i = \sum_i \eta_i(t)x_i

and try to substitute these into (3.2).

Observe that

|x| + |y(t)|

= | 1/3 \sum_i x_i | + | \sum_i \eta_i x_i |

\leq | 1/3 \sum_i x_i | + | \sum_i x_i / 3 | + | \sum_i (\eta_i - 1/3)x_i |

&\leq | \sum_i x_i | + | \sum_i (\eta_i - 1/3)x_i |

and this should give what we want on the RHS of the formula you're asking about.

Source Link
Yemon Choi
  • 25.8k
  • 9
  • 69
  • 156
Loading