Skip to main content
9 events
when toggle format what by license comment
May 26, 2021 at 13:40 vote accept C.F.G
Apr 20, 2021 at 0:23 answer added C.F.G timeline score: 3
Apr 19, 2021 at 18:18 comment added Willie Wong @C.F.G ... hence a comment, just the mention that it is relevant, and not a vote to close as duplicate.
Apr 19, 2021 at 18:00 comment added Igor Belegradek Yes, I think closed irreductible manifolds of nonnegative curvature operator are diffeomorphic to locally symmetric spaces, see e.g. section 2.4 of arxiv.org/pdf/1511.07899.pdf.
Apr 19, 2021 at 17:53 comment added C.F.G @IgorBelegradek: I am not sure, but I think so: "all closed manifolds of nonnegative curvature operator are diffeomorphic to locally symmetric spaces?" Someone argued non rigorously like this: a nonnegative curvature operator is of positive curvature operator or its holonomy is not of full rank. Does this help to figure out what is the right statement?
Apr 19, 2021 at 17:47 comment added C.F.G @WillieWong: my question is different from that linked MO.
Apr 19, 2021 at 17:46 comment added Igor Belegradek If you slightly deform the standard metric on the unit sphere, you get a metric if positive curvature operator which is not symmetric. The same will happen if you slightly deform a spherical space form. Are you asking if all closed manifolds of nonnegative curvature operator are diffeomorphic to locally symmetric spaces?
Apr 19, 2021 at 16:58 comment added Willie Wong mathoverflow.net/a/264899/3948 seems relevant.
Apr 19, 2021 at 16:49 history asked C.F.G CC BY-SA 4.0