Timeline for Operator norm of difference of matrix decompositions
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
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| Apr 20, 2021 at 6:44 | comment | added | Denis Serre | @HeinrichA. See my edit: even if we impose an a priori bound, the map $X\mapsto L$ is not Lipschitz. | |
| Apr 20, 2021 at 6:43 | history | edited | Denis Serre | CC BY-SA 4.0 |
added 582 characters in body
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| Apr 20, 2021 at 6:26 | vote | accept | Heinrich A | ||
| Apr 20, 2021 at 6:26 | vote | accept | Heinrich A | ||
| Apr 20, 2021 at 6:26 | |||||
| Apr 19, 2021 at 15:07 | comment | added | Heinrich A | Thanks very much for the helpful answer! I was wondering whether the composition would be globally Lipschitz if I werer to introduce the assumption that the columns entries of the matrices $\mathbf{A}$, $\mathbf{B}$ (and therefore also their square roots and Cholesky decompositions) are bounded. | |
| Apr 19, 2021 at 14:41 | history | answered | Denis Serre | CC BY-SA 4.0 |