Skip to main content
3 events
when toggle format what by license comment
Apr 14, 2021 at 20:04 comment added Iosif Pinelis @AzadTasan : Without squaring $f'/f$, the integral will in general exist only in the principal value en.wikipedia.org/wiki/Cauchy_principal_value sense; consider e.g. $f(x)\equiv x-1/2$. When you do square $f'/f$, even the principal value may be infinite.
Apr 14, 2021 at 19:51 comment added Azad Tasan Well that is slightly disappointing but I see your point. Thanks very much. I'll have to be more careful with my bounds getting there. I am a little confused as to why without the square I can bound it from above then, do you have an idea why that is?
Apr 14, 2021 at 19:14 history answered Iosif Pinelis CC BY-SA 4.0