Timeline for Integral bound for square of log derivative
Current License: CC BY-SA 4.0
3 events
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Apr 14, 2021 at 20:04 | comment | added | Iosif Pinelis | @AzadTasan : Without squaring $f'/f$, the integral will in general exist only in the principal value en.wikipedia.org/wiki/Cauchy_principal_value sense; consider e.g. $f(x)\equiv x-1/2$. When you do square $f'/f$, even the principal value may be infinite. | |
Apr 14, 2021 at 19:51 | comment | added | Azad Tasan | Well that is slightly disappointing but I see your point. Thanks very much. I'll have to be more careful with my bounds getting there. I am a little confused as to why without the square I can bound it from above then, do you have an idea why that is? | |
Apr 14, 2021 at 19:14 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |