Timeline for Eigenvalues convolution-type operator
Current License: CC BY-SA 2.5
11 events
when toggle format | what | by | license | comment | |
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S Jan 29, 2011 at 20:27 | vote | accept | CommunityBot | moved from User.Id=5295 by developer User.Id=481663 | |
Jan 29, 2011 at 20:27 | vote | accept | CommunityBot | moved from User.Id=5295 by developer User.Id=481663 | |
S Jan 29, 2011 at 20:27 | |||||
Sep 17, 2010 at 13:50 | vote | accept | CommunityBot | moved from User.Id=5295 by developer User.Id=481663 | |
Jan 29, 2011 at 20:27 | |||||
Sep 17, 2010 at 12:39 | vote | accept | CommunityBot | moved from User.Id=5295 by developer User.Id=481663 | |
Sep 17, 2010 at 13:36 | |||||
Sep 16, 2010 at 21:49 | vote | accept | CommunityBot | moved from User.Id=5295 by developer User.Id=481663 | |
Sep 17, 2010 at 12:39 | |||||
Sep 16, 2010 at 21:14 | answer | added | Julián Aguirre | timeline score: 2 | |
Sep 16, 2010 at 20:53 | answer | added | Helge | timeline score: 2 | |
Sep 16, 2010 at 20:42 | comment | added | Jonas T | @Julián Aguirre: I modified it a bit, $H_1(x)$ is the Fourier transform of the $\textrm{circ}$-function. | |
Sep 16, 2010 at 20:41 | history | edited | Jonas T | CC BY-SA 2.5 |
added 40 characters in body; deleted 1 characters in body
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Sep 16, 2010 at 20:23 | comment | added | Julián Aguirre | For large $x>0$, $J_1(x)$ is asymptotic to $\sqrt{2/(\pi x)}\cos(x-3\pi/4)$, so that it is not in $L^p$ for $1\le p\le 2$. The Fourier transform of $J_1(x)$ is unbounded with support in $[-1,1]$, so that $T$ does not map $L^2$ into itself. | |
Sep 16, 2010 at 19:28 | history | asked | Jonas T | CC BY-SA 2.5 |