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Apr 14, 2021 at 2:20 comment added SashaP Galois theory of perfect fields is, in fact, as hard as the Galois theory of general fields: if $k$ is a file of characteristic $p$ then its finite separable extensions are in bijection with finite (necessarily separable) extensions of its perfection $k_{perf}=colim(k\xrightarrow{x\mapsto x^p} k\to \dots)$
Apr 13, 2021 at 20:24 history became hot network question
Apr 13, 2021 at 14:13 history edited JNS CC BY-SA 4.0
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Apr 13, 2021 at 13:31 comment added Emil Jeřábek Your example field is in fact already a counterexample. For instance, where is the $l$-th root of $x$ for prime $l\ne p$?
Apr 13, 2021 at 12:54 vote accept JNS
Apr 13, 2021 at 12:46 answer added YCor timeline score: 11
Apr 13, 2021 at 12:40 comment added JNS Yes, I meant same degree, thanks. I edited it.
Apr 13, 2021 at 12:39 history edited JNS CC BY-SA 4.0
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Apr 13, 2021 at 12:37 comment added LSpice Presumably, in (2), you want $L$ and $L'$ to be of the same degree? The property you are asking for seems closely related to being quasi-finite.
Apr 13, 2021 at 12:23 history asked JNS CC BY-SA 4.0